$f\left(x\right)=\:\left(\left(\frac{1}{x}\right)+\left(\frac{x}{x+3}\right)\right)$
$\frac{x-9}{\left(4-x\right)\left(x-4\right)}$
$\left(x+8\right)\left(9x-3\right)$
$\lim_{x\to5}\left(\frac{x-3}{2x}\right)^{\frac{x+3}{x}}$
$\frac{x^2}{3}-\frac{x}{5}+6$
$-8\frac{1}{2}^3$
$\frac{d^3}{dx^3}\left(x^3-2x^2-5x+2\right)$
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