$\left(6^2\cdot7^3\right)^5$
$\frac{x^{2}-5x+24}{x^{2}-16x+24}$
$\int\frac{x+7}{5x^2+32x-21}dx$
$\left(-3\right)^3-\left(+7\right)^0+\left(-11\right)^5\left(-11\right)^3$
$\frac{x^2-3}{9-x}=0$
$4\:x^2\:+8\:x\:+3=0$
$\frac{4m^6}{7n}\cdot\frac{m^4}{7}$
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