$\lim_{x\to\infty}\left(1+\frac{1}{x}\right)^2$

$3p^3+4+2p^3+3p^4-6$

$\lim_{x\to0}\left(\frac{1}{x}-\frac{2}{\ln\left(1+2x\right)}\right)$

$\frac{dy}{dx}=\frac{\left(3x^2-5\right)}{sin\left(y\right)}$

$q\left(x\right)=\left(3x^3+4x\right)^x$

$2e^{x+1}\:=\:9$

$\left(11x-10y\right)^2$