$\int_7^8\left(\frac{1}{1+x^2}\right)dx$
$2x+3\left(-2x+5\right)=5-2\left(2x+4\right)$
$\left(4y^2-1\right)\left(16y^4+4y^2+1\right)$
$964+162.703+64.80$
$2.6r\:+\:1.3\:=\:-16.9$
$-8-w>-7$
$c-9=6$
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