$\int6x^2e^{x^3-1}dx$
$w^2-3w-40=0$
$\frac{\tan^2\left(x\right)}{\sin\left(x\right)}=\frac{\sin\left(x\right)}{\cos^2\left(x\right)}$
$6t^2+-8t^2$
$7^{-3}\cdot7^4$
$0-\left(-41\right)-28$
$\sqrt{1^2}+0^2+\sqrt{3}^2$
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