The integral of a function times a constant ($11$) is equal to the constant times the integral of the function

Apply the formula: $\int\frac{n}{ax+b}dx$$=\frac{n}{a}\ln\left(ax+b\right)+C$, where $a=-7$, $b=3$ and $n=1$

Multiply the fraction and term in $11\cdot \left(\frac{1}{-7}\right)\ln\left|-7x+3\right|$

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$