$18x^3y-8xy^3$
$\frac{uv^{-1}}{2uv^{-2}}$
$3x^2y^2\sin\left(x\right)dx-\sin\left(x\right)dy=0$
$\frac{\left(\cos^2x\right)dy}{\left(\sin\left(x\right)\right)}=\frac{ydx}{\cos^2\left(x\right)}$
$\frac{dy}{dx}=\frac{ye^x}{\left(1+y^2\right)}$
$0.5\:\left(2x\:-\:0.1\right)^2$
$3x-4y=6$
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