$\frac{\left(6x^5+4x^3-1\right)}{\left(2x^2\right)}$

$f\left(x\right)=3x\left(x-6\right)^2\left(x-1\right)^2$

$-9x-6x-2x$

$\frac{dy}{dx}=\frac{\left(y^2+y\right)}{x}$

$\left(g^{h+1}\right)^2$

$\int\left(\frac{y^5}{b}+a\right)^{\frac{7}{8}}y^4dy$

$\left(-e^{-\infty}\infty^2+2\left(-e^{-\infty}\infty-e^{\infty}\right)\right)-\left(-e^{-2}2^2+2\left(-e^{-2}2-e^2\right)\right)$