$\int2x^2\left(2x^3+1\right)^4dx$

$24=3z-12$

$4x^2-20x+25\ge\:0$

$\frac{1}{y}\cdot\frac{dy}{dx}=4x\cdot\ln\left(x\right)$

$\frac{\left(cot\theta\:+1\right)\left(cot\theta\:+1\right)-csc^2\theta\:}{cot\theta\:}$

$\left(-2bu^4\right)^5$

$\frac{dy}{dx}=\frac{y\cdot cosx}{1+y^2}\:y\left(0\right)=1$