$3x+1.5\left(2x+8\right)$
$4^2-2^2$
$\left(45-18+81\right)$
$\lim_{x\to\infty}\left(\frac{\left(e^{\left(-0.1\left(x+1\right)^{0.5}\right)}\right)}{\left(e^{\left(-0.1\left(x\right)^{0.5}\right)}\right)}\right)$
$\int x^2\left(3-2x\right)dx$
$10m^2-5m$
$\frac{1}{9}m^6-1$
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