$\left(2m-1\right)^2$
$-\sin\left(x\right)=-20\sin\left(x\right)$
$\frac{2x^2}{x^2+4}$
$\left(4y^3+15\right)\left(4x^3+15\right)$
$\frac{\sin^2\left(x\right)}{\cos^2\left(x\right)-\cos\left(x\right)}=1+\frac{1}{\cos\left(x\right)}$
$+3000-2020$
$\left(-12+15\right)\cdot\left(-1\right)$
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