$\frac{4x^2-2}{x+1}$
$3x^2y+3xy^3-3x^2y+5y^3x-6yx^2$
$\int_0^5\pi\left(\sqrt{x}+3\right)^2dx$
$\frac{\left(1-cos\left(4x\right)\right)}{2}=sin^4x$
$\frac{1}{2}x+2$
$-\frac{3x^4}{-x^2}$
$16cos^4x=\:8cos2x+2cos4x+6$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!