x2y=5x^2y=5x2y=5
π∫13(2x2+1)2dx\pi\int_1^3\left(2x^2+1\right)^2dxπ∫13(2x2+1)2dx
−7−2(−13)(12)(5+−2)-7-2\left(-\frac{1}{3}\right)\left(\frac{1}{2}\right)\left(5+-2\right)−7−2(−31)(21)(5+−2)
limx→−3(x2−x−54)\lim_{x\to-3}\left(x^2-x-54\right)x→−3lim(x2−x−54)
(x−3) (x+5)>0\left(x-3\right)\:\left(x+5\right)>0(x−3)(x+5)>0
∫x24+x4dx\int x^2\sqrt[4]{4+x}dx∫x244+xdx
−14(4+11s)-14\left(4+11s\right)−14(4+11s)
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