$-20v=-340$
$\left(2x^3+xy^2\right)dx\:+\left(x^2y+2y^3\right)dy=0$
$-16=0.2b$
$\left(6-x\right)\left(x+4\right)$
$y^2-25$
$a^2+4^2+4ab-x^2-2ax-a^2$
$\frac{dy}{dx}=\frac{x}{2y-4}$
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