$\frac{dy}{dx}=\frac{e^{x-y}}{1+e^x}$
$4+7+2-7-3$
$\left(3x+8\right)x\left(3x-8\right)$
$1-\frac{2}{\infty\:\:}$
$\int\frac{\left(6-x\right)}{\sqrt{3x^2-12x}}dx$
$\frac{dy}{dx}=\frac{x}{-2y}$
$\lim_{x\to0}\left(\frac{3e^x-3}{\ln\left(x+1\right)-x^3}\right)$
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