$4x+2\cdot2x-3$

$\frac{d}{dx}\left(x^4-y^5=0\right)$

$2+10+14$

$\left(\sqrt[3]{x+h}\right)^2$

$\cos\left(x\right)\left(1+\sec\left(x\right)\right)\left(\cos\left(x\right)-1\right)=-\sin^2\left(x\right)$

$-5.55\:-\:-1.25$

$\lim_{x\to-5}\left(\frac{x^2+16x+55}{ln\left(3x+16\right)}\right)$