$y=\ln\left(x^2\right)-\arctan\left(\frac{x}{4}\right)$
$\int x^{\frac{-3}{2}}\ln\left(x\right)^2dx$
$\int\frac{x^2+8}{x\left(x^2+16\right)}dx$
$12x^3-90^2-24x+12$
$2x^7+8x^2$
$\frac{1}{9}x^2+\frac{20}{3}x+100$
$4x^{2}+72xy+54y^{2}$
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