$\frac{\left(4x-21\right)}{x-9}\ge3$
$0.02a=2$
$\lim_{x\to0}\left(\frac{x^2+x-6}{x^2-3x+2}\right)$
$5x^2+21x+18=0$
$\left(3x-2y+1\right)^3$
$-3518-3$
$9.9x^4\:-\:30x^3y\:+\:25xy$
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