$\frac{x^3+6x+2}{x-3}$
$\frac{dy}{dx}=\left(x+1\right)+yx+y$
$x^2-x>2\left(1-x\right)$
$\left(4xyz-2x\right)\left(6xyz-\frac{3}{7}\right)$
$f^4-4$
$0=1-\sin\left(x\right)-2\cos^2\left(x\right)$
$\lim_{x\to2}\left(\frac{x^2-2x}{8-6x+x^2}\right)$
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