$\int\left(-5\sin t\right)dt$
$-4\left(x^2-4x+8\right)$
$9x^2+6x+4$
$\left(9x-17\right)\left(9x+17\right)$
$\lim_{x\to\infty}\frac{\left(2\left(x-3\right)\right)}{x^2+9}$
$\left(x^5-2y\right)^3$
$\left(5x+7\right)\ge2$
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