$\frac{d}{dx}\left(y=\frac{x^2\left(x-1\right)^3}{x+3}\right)$
$\csc\:2\:x-1=0$
$6m^2+7m^2-10m^2+m^2-5m^2+4m^2$
$1-\frac{\cos^2x}{1+\sin\left(x\right)}$
$-2x+5y-6z+3x-7y+9z-4x+2y+2z$
$\int\frac{x+3}{4x^2-4x+1}dx$
$400^{10}+40^5+1$
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