$cosx=\frac{3}{7}$
$x^4m+x^5+3yx$
$1-3x^2+x+1$
$\left(3z^3+2x\right)\left(3z^3-2x\right)$
$\frac{6x-12y}{18-36y}$
$8+\left[9-\left\{6-\left(5-4\right)\right\}\right]+14-\left\{11-\left[7-\left(3-2\right)\right]\right\}$
$y'-xy^{\frac{1}{2}}=0$
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