$g\left(x\right)=\frac{\left(2x-3\right)^2}{4-2x}$
$4a^2+2ab$
$\lim_{x\to\infty}\left(\frac{5x^4+20x^3}{1000x^3+6}\right)$
$\left(\frac{a}{7}-\frac{b}{2}\right)^2$
$2x-3y+z=3$
$10\cdot3\:\frac{1}{10}$
$\left(2a^2+2a\right)-x\left(a^2+2a\right)$
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