$\int\frac{x^2-5x+3}{x^2-6x+8}dx$
$\int_0^4\frac{3}{32}\left(4x-x^2\right)dx$
$7x^2+x-10-2x\cdot1$
$\lim_{x\to4}\left(\frac{x^2-8x+16}{x^2-7x+12}\right)$
$\int\frac{7x^4}{\left(x^5+3\right)^5}dx$
$\frac{1}{x+2}>1$
$\lim_{t\to2}\left(\frac{x^3-8}{x-2}\right)$
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