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f(x)=(8-3x)/(10x^2+13x+-3)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫(8−3x)10x2+13x−3dx\int\frac{\left(8-3x\right)}{10x^2+13x-3}dx

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Final answer to the exercise

199340ln⁡∣20(x+1320)17−1∣−199340ln⁡∣13+20x17+1∣−320ln⁡∣20x−4∣−320ln⁡∣20x+30∣+C0\frac{199}{340}\ln\left|\frac{20\left(x+\frac{13}{20}\right)}{17}-1\right|-\frac{199}{340}\ln\left|\frac{13+20x}{17}+1\right|-\frac{3}{20}\ln\left|20x-4\right|-\frac{3}{20}\ln\left|20x+30\right|+C_0

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∫(8−3x)10x2+13x−3 dx
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