$\sqrt{\frac{y^4}{16}}$
$\int\csc^2\left(6x+3\right)dx$
$\left(-7.24\right)+9.1$
$\frac{x}{\:x+2}-\frac{1}{x-2}=\frac{8}{x^2-4}$
$\frac{x^3+6x-10}{x+2}$
$h\left(t\right)=-10\cos\left(\frac{2p}{150}t\right)+10$
$b^2-2b-35=0$
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