$\frac{\left(3x+6\right)}{8}=\frac{\left(3x-3\right)}{16}$
$-24a+9a-35a$
$\int\left(2x+3\right)^{-1}dx$
$\left(a^2b+2\right)\left(a^2b-10\right)$
$ln\sqrt[6]{t}$
$+1-\left(+3-\left(-8\right)-\left(+8\right)\right)+\left(+6+\left(+8\right):\left(+4\right)\right)$
$x^2+300x-60000$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!