$\frac{a^2+2a+8}{a+2}$
$\lim_{x\to0}\left(\frac{ln\left(sen\left(2x\right)\right)}{ln\left(senx\right)}\right)$
$\left(2b^5\right)^3$
$\left(x+a^2\right)\left(x-b^2\right)$
$\left(2+5\right)\left(2+5\right)^2$
$-36+4x$
$\left(+3\right).\left(-5\right)$
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