$\left(\tan b+\sec b\right)\left(1-\sin b\right)=\cos b$

$3x-17>0$

$\left(3a+bc\right)^3$

$6-\left(2-9\right)-2\left[5-8-\left(-9-2\right)\right]$

$7\left(2u+7\right)=7\left(2u+7\right)$

$\int\frac{x^2-3x-7}{\left(2x+3\right)\left(x+1\right)}dx$

$\frac{16x^2-25y^4}{4x-5y^2}$