$\int\frac{x+2}{\sqrt{7-6x-x^2}}dx$
$x+\sqrt{2x+1}=7$
$\frac{3}{2x-2}\ge\:\frac{1}{2x+1}$
$\:\left(\frac{2x}{5}-3\right)\cdot\left(\frac{2x}{5}+3\right)$
$\frac{\left(1+sinx\right)}{cosx}+\frac{cosx}{1+sinx}=4$
$498^2$
$\left(x+2\right)^2=_{+4x+4}$
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