$\frac{4^{-3}}{4^{-7}}$
$\left(140-3x\right)^2$
$\left(x-4\right)\left(2x+3\right)$
$24\:\cdot\:-27$
$4x^4-3x^3+26x^2-27x-90$
$\sqrt{-3}\cdot\sqrt{-5}$
$g^3+g^2+\frac{x}{4}+\frac{1}{27}$
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