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f(x)=cos(2x)^3sin(2x)^6−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫cos⁡3(2x)sin⁡6(2x)dx\int\cos^3\left(2x\right)\sin^6\left(2x\right)dx

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Final answer to the exercise

−sin⁡(2x)5cos⁡(2x)418+5cos⁡(2x)2sin⁡(2x)126+163sin⁡(2x)−142cos⁡(2x)4sin⁡(2x)+−2cos⁡(2x)2sin⁡(2x)63+−5sin⁡(2x)3cos⁡(2x)4126+C0\frac{-\sin\left(2x\right)^{5}\cos\left(2x\right)^{4}}{18}+\frac{5\cos\left(2x\right)^{2}\sin\left(2x\right)}{126}+\frac{1}{63}\sin\left(2x\right)-\frac{1}{42}\cos\left(2x\right)^{4}\sin\left(2x\right)+\frac{-2\cos\left(2x\right)^{2}\sin\left(2x\right)}{63}+\frac{-5\sin\left(2x\right)^{3}\cos\left(2x\right)^{4}}{126}+C_0

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∫cos3(2x)sin6(2x)dx
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