$\frac{2x^3}{x^2-1}$
$-2m+250m^2$
$\frac{dy}{dt}=y\:+\:1\:$
$xy\:=\:1\:+\:x^2$
$\int_2^5\left(x+5\right)\left(3x-5\right)dx$
$1-2\:\:x\:16$
$\lim_{x\to\infty}\left(x\right)^{\left(3cot\:x\right)}$
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