$6x-3=3x-18$
$\left(14^5\right)^5$
$\lim_{x\to0}\left(\frac{k}{k^3-2\arctan\:\left(k\right)+4}\right)$
$\frac{ab}{n}+\frac{ac}{d}$
$\int_1^n\left(\frac{x}{x^2-x-6}\right)dx$
$\:\:5^3-4^4$
$\frac{dy}{dx}=\left(4x^3-6x\right)\cos\left(x^4-3x^2+11\right)$
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