$a^5b^3+a^2b^5$
$\left(6a+7b\right)^2$
$\int\left(x\:arctan\left(\sqrt{x}\right)\right)dx$
$\frac{1+m^5}{1-m}$
$\left[46\:-\:13\right]\:-\:\left[24\:-\left(-32\right)\right]\:$
$2x+6>7x-6$
$\frac{x^3-2x+1}{x^2-5x}$
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