$\left(+4\right)-\left(+2\right)-\left(-5\right)+\left(-1\right)-\left(-2\right)$
$\lim_{x\to-4}\sqrt[3]{\frac{3-4x}{2-x}}$
$xy'\:+\:\frac{y}{lnx}=9x^3$
$6c=24$
$2x^2-2x\ge4$
$\tan\left(90-x\right)=\frac{1}{\tan\left(x\right)}$
$\frac{10}{\left(1+10x\right)^2}$
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