$\left(x^2+9\right)\frac{dy}{dx}=-x\:y$
$\lim_{x\to\infty}\left(\frac{\ln\left(x\right)}{x^2-1}\right)$
$\frac{d}{dx}5x^3+3x-8$
$3x\ge x+7$
$4x^2-18x+13$
$\int\left(-9\sqrt{x}\right)dx$
$2x^2-21x-11$
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