$9\cdot18,9$
$\frac{d}{dx}\:\frac{3}{4}x^4$
$\frac{\left(x+\frac{1}{2}y\right)}{2}=1$
$\frac{x^2-4}{x-2\:}$
$-3+4-1-1-1-5$
$3x+5<x+13$
$5r-7r$
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