$400x^2+20x-20$
$\tan\left(x\right)\sec^4\left(x\right)$
$\frac{\left(x^3-3x^2+6-2x\right)}{x-3}$
$-8-\left(13-6\right)$
$\left(x+5\right)^2>\left(2x-5\right)^2+x\left(x-2\right)\:$
$y=2x-6y$
$\left(m^9\:-\:3\right)^2$
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