$m^2-18m=_{-77}$
$\sqrt[3]{\frac{48}{\sqrt[3]{-6}}}$
$4-6x\ge x-10$
$1+6+13-7$
$\left(3x^2+4xy^2\right)^2$
$\left(-7\right)-\left(-9\right)+1$
$3a+12ab$
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