$$x^2+16x+1=0$$

$$\left(t^{2}+1\right)^{dy}dt=2y$$

$$\frac{\left(-7.9\right)^{10}}{\left(-7.9\right)^4}$$

$$-\left(-3\right)^{6}:\left(-3\right)^{4}$$

$$\frac{8}{\frac{8}{0}}$$

$$z^2-5z=-6$$

$$\left|5\right|-\left|-5\right|\left(-5\right)$$