$\left(6x+10y\right)dx+\left(10x-4y^2\:\right)dy=0$

$\frac{1}{x^3+2x^2+x}$

$\lim_{x\to\infty}\left(1-\frac{1}{x}\right)^{6x}$

$\frac{\left(2a^{-1}b^2\right)^2}{\left(a^{-3}b\right)^3}$

$10-5a$

$8x+\left(4y-2x+3\right)-\left(5+3y\right)$

$4\left(-2\right)\left(3\right)-2\left(3\right)^{2}-\left(-2\right)^{2}$