$cos\frac{1}{4}x=\frac{-\sqrt{2}}{2}$
$\lim_{x\to1}-1$
$x.\frac{dy}{dx}+3y=x^3$
$5\:-\:\left[-\left(16\:-\:9\right)\:-\:\left(-17\:-\:13\right)\right]$
$x+-68=-129$
$\lim_{x\to4\:\:}\left(\frac{x-4}{x^2-x-4}\right)$
$\left(6x+5\right)-\left(8x+15\right)$
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