$16x^2-16x+1$
$-\frac{90}{10}$
$\lim_{x\to\infty}\frac{2^x-3^x}{3^x+5^x}$
$1+\tan^2\left(a\right)=\sec^2\left(a\right)$
$x^2+8x-15$
$5\cdot37$
$\frac{x^4+2}{x^2+2x+5}$
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