$16+x=12$
$\int\frac{1}{\left(x^2+8\right)\left(x^2-8\right)}dx$
$\int\:\frac{s\left(s^3-4\right)}{\sqrt{s^5-10s^2+6}}dx$
$\left(5m^3-3n^4\right)^2$
$19\:=\:9\:+\:2g$
$-1\:-\:-3$
$\left(-21ab^2\right)+\left(14ab^2\right)$
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