$\left(8x\:+1\:\right)^3\:\:\:\:\:\:\:\:\:\:$
$\left(_{-3^3}\right)$
$o^2+16o+1$
$3\cos\left(x\right)=3-3\sin\left(x\right)$
$\frac{d}{dx}\left(4cos^{-1}\left(2x^3\right)\right)$
$346.9\cdot3.46$
$x^2+4x+20.25$
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