$a^2\:-\:4^2$
$2x\:+6\:<4$
$\frac{6x^2-7x+1}{-4x+4}$
$-11\:+\:s\:=\:-1$
$\frac{\left(x^3+8x^2+6x+1\right)}{\left(x+5\right)}$
$2x\left(x^2-4x+3\right)$
$\int9x\left(7-x^{-4}\right)dx$
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