$-4x+6\le\:6$
$\frac{\left(20x^2\right)}{\left(4x^3\right)}$
$\frac{d^3}{dx^3}\left(e^2\cdot\cos\left(2\right)\right)$
$\left(7x^{6}+5\right)\left(7x^{6}+10\right)+\left(8a^{6}+2y\right)^{3}$
$\frac{x}{-5}=\:17$
$9\left(3x+5\right)-2\left(5+x\right)\left(x-5\right)-45$
$\left(141\right)^3$
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