$\frac{5x-9}{3}+\frac{x}{2}=10$
$xy\:dx-\left(x^2+3y^2\right)dy=0$
$\frac{dy}{dx}=\frac{\left(x^2-1\right)}{y^3+1}$
$\frac{\left(4x^4+3x^3+11x^2\right)}{\left(x+4\right)}$
$9a^2-30a-25$
$\left(4m-3\right)^2+2\left(4m-3\right)-24=0$
$3x^3-2\left(x^2+3\right)$
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