$\frac{d}{dx}\left(x^3+y^3\right)=6$
$\frac{6\sin\left(x\right)+3\tan\left(x\right)}{\tan\left(x\right)}$
$\left(u^5\right)^3u^4$
$\lim_{x\to-1}\left(\frac{-1}{3sin\left(\pi x\right)}\right)$
$-3\:.\:3\:.\:\frac{-4}{9}$
$-a+b+2b+2c+3a+2c+3b$
$6am\left(2+a\right)$
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