1−[2−3]1-\left[2-3\right]1−[2−3]
5 − x =125\:-\:x\:=125−x=12
∫csc(3x)x2dx\int\frac{\csc\left(\frac{3}{x}\right)}{x^2}dx∫x2csc(x3)dx
f(x)=4x2−16x+15f\left(x\right)=4x^2-16x+15f(x)=4x2−16x+15
(4x2−6)(4x2−3)\left(4x^2-6\right)\left(4x^2-3\right)(4x2−6)(4x2−3)
m2+2m2+7m2m^2+2m^2+7m^2m2+2m2+7m2
7−5m+10m7-5m+10m7−5m+10m
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